It seems I skipped too many chapters in Feynman’s second volume of Lectures (on electromagnetism) and so I have to return to that before getting back to quantum physics. So let me just do that in the next couple of posts. I’ll have to start with the basics: ** Maxwell’s equations**.

Indeed, electromagnetic phenomena are described by a set of four equations known as Maxwell’s equations. They relate two fields: the electric field (**E**) and the magnetic field (**B**). The electric field appears when we have electric charges: positive (e.g. protons or positively charged ions) or negative (e.g. electrons or negatively charged ions). That’s obvious.

In contrast, there is no such thing as ‘magnetic charges’. The magnetic field appears only when the electric field *changes*, or when charges *move*. In turn, the *change *in the magnetic field causes an electric field, and that’s how electromagnetic radiation basically works: a changing electric field causes a magnetic field, and the build-up of that magnetic field (so that’s a *changing* magnetic field) causes a build-up of an electric field, and so on and so on.

OK. That’s obvious too. But how does it work *exactly*? Before explaining this, I need to point out some more ‘obvious’ things:

**1.** From Maxwell’s equations, we can calculate the magnitude of **E** and **B**. Indeed, a specific functional form for **E** and **B **is what we get when we *solve *Maxwell’s set of equations, and we’ll jot down that solution in a moment–even if I am afraid you will shake your head when you see it. The point to note is that what we get as a solution for **E** and **B** is a solution *in a particular frame of reference only*: if we switch to another reference frame, **E** and **B** will look different.

** Huh? **Yes. According to the principle of relativity, we cannot say which charges are ‘stationary’ and which charges are ‘moving’ in any absolute sense: it all depends on our frame our reference.

**But…** Yes? **Then if we put an electric charge in these fields, the force on it will also be different?**

Yes. Forces also look different when moving from one reference to another.

**But…** Yes? **The physical effect surely has to be the same, regardless of the reference frame?**

Yes. The point is that, if we look at an electric charge q moving along a current-carrying wire in a coordinate system at rest *with respect to the wire*, with the same velocity (*v*_{0}) as the conduction electrons (** v**), then the whole force on the electric charge will be ‘magnetic’:

**F**= q

*v*_{0}×

**B**and

**E**= 0. Now, if we’re looking at the same situation from a frame of reference that is

*moving with q*, then our charge is at rest, and so there can be no magnetic force on it. Hence, the force on it must come from an electric field!

*But what produces the electric field? Our current-carrying wire is supposed to be neutral!*

Well… It turns out that our ‘neutral’ wire appears to be charged when moving. We’ll explain – in very much detail – why this is so later. Now, you should just note that “we should not attach too much reality to **E** and **B**, because they appear in different ‘mixtures’ in different coordinate systems”, as Feynman puts it. In fact, you may or may not heard that magnetism is actually nothing but a “relativistic effect” of electricity. Well… That’s true, but we’ll also explain how that works later only. Let’s not jump the gun.

**2.** The remark above is related to the other ‘obvious’ thing I wanted to say before presenting Maxwell’s equations: fields are very useful to describe what’s going on but, when everything is said and done, what we really want to know is what *force* will be acting on a charge, because that’s what’s going to tell us *how that charge is going to move*. In other words, we want to find the equations of motion, and the force determines how the charge’s *momentum *will change: **F** = d**p**/dt = d(m** v**)/dt (i.e. Newton’s equation of motion).

So how does that work? We’ve given the formula before:

**F** = q(**E** + ** v**×

**B**) = q

**E**+ q(

**×**

*v***B**)

This is a sum of two vectors:

- q
**E**is the ‘electric force: that force is in the same direction as the electric field, but with a magnitude equal to q times E. [Note I use a bold letter (**E**) for a vector (which we may define as some quantity with a*direction*) and a non-bold letter (E) for its magnitude.] - q(
×*v***B**) is the ‘magnetic’ force: that force depends on*both**v**as well as*on**B**. Its direction is given by the so-called right-hand rule for a vector cross-product (as opposed to a dot product, which is denoted by a dot (·) and which yields a scalar instead of a new vector).

That right-hand rule is illustrated below. Note that, if we switch **a** and **b**, the **b**×**a** vector will point downwards. The magnitude of q(** v**×

**B**) is given by |

*×*

**v****B**

**|**

**=**|

*||*

**v****B**

**|**sinθ (with θ the angle between

**and**

*v***B**).

We know the direction of * v *(because we’re talking about some charge that is moving here) but what direction is

**B**? It’s time to be a bit more systematic now.

**Flux and circulation**

In order to understand Maxwell’s equations, one needs to understand two concepts related to a vector field: flux and circulation. The two concepts are best illustrated referring to a vector field describing the flow of a liquid:

**1.** If we have a surface, the * flux* will give us the

*net*amount of fluid going out through the surface per unit time. The illustration below (which I took from Feynman’s Lectures) gives us not only the general idea but a formal definition as well:

**2.** The concept of * circulation* is linked to the idea of some

*net*rotational motion around some loop. In fact, that’s exactly what it describes. I’ll again use Feynman’s illustration (and description) because I couldn’t find anything better.

Diagram (a) gives us the velocity field in the liquid. Now, imagine a tube (of uniform cross section) that follows some arbitrary closed curve, like in (b), and then imagine we’d suddenly freeze the liquid everywhere except inside the tube: the liquid in the tube would circulate as shown in (c). Formally, the circulation is defined as:

circulation = (the average tangential component)·(the distance around)

OK. So far, so good. Back to electromagnetism.

**E and B**

We’re familiar with the electric field **E** from our high school physics course. Indeed, you’ll probably recognize the two examples below: (a) a (positive) charge near a (neutral) conducting sheet, and (b) two opposite charges next to each other. Note the convention: the field lines emanate from the positive charge. *Does that mean that the force is in that direction too?* Yes. But remember: if a particle is attracted to another, the latter particle is attracted to the former too! So there’s a force in both directions !

What more can we say about this? Well… It is clear that the field** E** is directed radially. In terms of our flux and circulation concepts, we say that there’s an *outgoing flux* from the (positive) point charge. Furthermore, it would seem to be pretty obvious (we’d need to show why, but we won’t do that here: just look at Coulomb’s Law once again) that the flux should be proportional to the charge, and it is: if we double the charge, the flux doubles too. That gives us Maxwell’s first equation:

flux of **E** through a *closed *surface = (the net charge inside)/ε_{0}

Note we’re talking a *closed *surface here, like a sphere for example–but it does not have to be a nice symmetric shape: Maxwell’s first equation is valid for *any *closed surface. The expression above is Coulomb’s Law, which you’ll also surely remember from your high school physics course: while it *looks* very different, it’s the same. It’s just because we’re using that flux concept here that we *seem* to be getting an entirely different expression. But so we’re not: it’s the same as Coulomb’s Law.

As for the ε_{0} factor, that’s just a constant that depends on the units we’re using to measure what we write above, so don’t worry about it. [I am noting it here because you’ll see it pop up later too.]

For **B**, we’ve got a similar-looking law:

flux of **B** through a closed surface = 0 (= zero = nil)

That’s *not* the same, you’ll say. Well… Yes and no. It’s the same really, but the zero on the right-hand side of the expression above says there’s no such thing as a ‘magnetic’ charge.

*Hmm…* But… *If we can’t create any flux of B, because ‘magnetic charges’ don’t exist, so how do we get magnetic fields then? *

Well… We wrote that above already, and you should remember it from your high school physics course as well: a magnetic field is created by (1) a moving charge (i.e. a flow or *flux* of electric current) or (2) a *changing* electric field.

Situation (1) is illustrated below: the current in the wire creates some *circulation *of **B** *around the wire*. How much? Not much: the magnetic effect is very small as compared to the electric effect (that has to do with magnetism being a relativistic effect of electricity but, as mentioned above, I’ll explain that later only). To be precise, the equation is the following:

*c*^{2}(circulation of **B**)= (flux of electric current)/ε_{0}

That *c*^{2} factor on the left-hand side becomes 1/*c*^{2} if we move it to the other side and, yes, *c *is the speed of light here – so you can see we’re talking a very small amount of circulation only indeed! [As for the ε_{0} factor, that’s just the same constant: it’s got to do with the units we’re using to measure stuff.]

One last point perhaps: what’s the direction of the circulation? Well… There’s a so-called right-hand grip rule for that, which is illustrated below.

OK. Enough about this. Let’s go to situation (2): a *changing* electric field. That effect is usually illustrated with Faraday’s original 1831 experiment, which is shown below with a more modern voltmeter 🙂 : when the wire on one side of the iron ring is connected to the battery, we’ll see a *transient *current on the other side. It’s *transient *only, so the current quickly disappears. That’s why transformers don’t work with DC. In fact, it is said that Faraday was quite disappointed to see that the current didn’t last! Likewise, when the wire is disconnected, we’ll briefly see another *transient* current.

So this effect is due to the *changing* electric field, which causes a changing magnetic field. But so where *is *that magnetic field? We’re talking currents here, aren’t we? Yes, you’re right. To understand why we have a transient current in the voltmeter, you need to understand yet another effect: a *changing* magnetic field causes an electric field, and so that’s what actually generates the transient current. However, what’s going on in the iron ring is the magnetic effect, and so that’s caused by the *changing* electric field as we connect/disconnect the battery to the wire. *Capito?*

I guess so… So what’s the equation that captures this situation, i.e. situation (2)? That equation involves both flux and circulation, so we’ll have a surface (*S*) as well as a curve (*C*). The equation is the following one: for any surface *S* (*not* closed this time because, if the surface was closed, it wouldn’t have an edge!), we have:

*c*^{2}(circulation of **B **around *C*)= d(flux of **E **through *S*)/dt

I mentioned above that the reverse is also true. A changing magnetic field causes an electric field, and the equation for that looks very similar, except that we don’t have the *c*^{2} factor:

circulation of **E **around *C *= d(flux of **B **through *S*)/dt

Let me quickly mention the presence of absence of that *c*^{2} or 1/*c*^{2} factor in the previous equations once again. It is interesting. It’s got nothing to do with the units. It’s really a proportionality factor: any change in **E** will only cause a *little* change in **B **(because of the 1/*c*^{2} factor in the first equation), but the reverse is *not* true: there’s no *c*^{2} in the second equation. Again, it’s got to do with magnetism being a relativistic effect of electricity, so the magnetic effect is, in most cases, tiny as compared to the electric effect, except when we’re talking charges that are moving at relativistic speeds (i.e. speeds close to *c*). As said, we’ll come back to that–later, much later. Let’s get back to Maxwell’s equations first.

**Maxwell’s equations**

We can now combine *all *of the equations above in one set, and so these are Maxwell’s four famous equations:

- The flux of
**E**through a*closed*surface = (the net charge inside)/ε_{0} - The circulation of
**E**around*C*= d(flux of**B**through*S*)/dt (with*C*the curve or edge around*S*) - The flux of
**B**through a*closed*surface = 0 *c*^{2}(circulation of**B**around*C*)= d(flux of**E**through*S*)/dt + (flux of electric current)/ε_{0}

From a mathematical point of view, this is a *set* of differential equations, and they are *not *easy to grasp intuitively. As Feynman puts it: “The laws of Newton were very simple to write down, but they had a lot of complicated consequences and it took us a long time to learn about them all. These laws are not nearly as simple to write down, which means that the consequences are going to be more elaborate and it will take us quite a lot of time to figure them all out.”

Indeed, Feynman needs about twenty (!) *Lectures* in that second Volume to show what it all implies, as he walks us through electrostatics, magnetostatics and various other ‘special’ cases before giving us the ‘complete’ or ‘general’ solution to the equations. This ‘general’ solution, in mathematical notation, is the following:

** Huh? What’s that?** Well… The four equations are the equations we explained already, but this time in mathematical notation: flux and circulation can be expressed much more elegantly using the differential operator

**∇**indeed. As for the solutions to Maxwell’s set of equations, you can see they are expressed using two other concepts: the

*scalar*potential

*Φ*and the vector potential

**.**

*A*Now, it is *not *my intention to summarize two dozen of Feynman’s *Lectures *in just a few lines, so I’ll have to leave you here for the moment.

[…]

** Huh? What?** What about my promise to show that magnetism is a relativistic effect of electricity indeed?

Well… I wanted to do that just now, but when I look at it, I realize that I’d end up copying most of Feynman’s little *exposé* on it and, hence, I’ll just refer you to that particular section. It’s really quite exciting but – as you might expect – it does take a bit of time to wrestle through it.

That being said, it really *does* give you a kind of an *Aha-Erlebnis *and, therefore, I really warmly recommend it ! Just click on the link ! 🙂