My dear readers – I haven’t published much lately, because I try to summarize my ideas now in short articles that might be suitable for publication in a journal. I think the latest one (on Einstein’s mass-energy relation) should be of interest. Let me just insert the summary here:

The radial velocity formula and the Planck-Einstein relation give us the *Zitterbewegung* (*zbw)* frequency (E = ħω = E/ħ) and *zbw* radius (*a* = *c*/ω = *c*ħ/m*c*^{2} = ħ/m*c*) of the electron. We interpret this by noting that the *c* = *a*ω identity gives us the E = m*c*^{2} = m*a*^{2}ω^{2} equation, which suggests we should combine the total energy (kinetic and potential) of *two *harmonic oscillators to explain the electron mass. We do so by interpreting the elementary wavefunction as a two-dimensional (harmonic) electromagnetic oscillation in real space which drives the pointlike charge along the *zbw* current ring. This implies a *dual *view of the reality of the real and imaginary part of the wavefunction:

- The
*x*=*a*cos(ωt) and*y*=*a*·sin(ωt) equations describe the motion of the pointlike charge. - As an electromagnetic oscillation, we write it as
*E*_{0}=*E*_{0}cos(ωt+π/2) +*i*·*E*_{0}·sin(ωt+π/2).

The magnitudes of the oscillation *a* and *E*_{0} are expressed in distance (*m*) and force per unit charge (N/C) respectively and are related because the energy of both oscillations is one and the same. The model – which implies the energy of the oscillation and, therefore, the effective mass of the electron is spread over the *zbw* disk – offers an equally intuitive explanation for the angular momentum, magnetic moment and the *g*-factor of charged spin-1/2 particles. Most importantly, the model also offers us an intuitive interpretation of Einstein’s enigmatic mass-energy equivalence relation. Going from the stationary to the moving reference frame, we argue that the plane of the *zbw *oscillation should be parallel to the direction of motion so as to be consistent with the results of the Stern-Gerlach experiment.

So… Well… Have fun with it ! I think I am going to sign off. 🙂 Yours – JL