I thought I’d stop blogging, but I can’t help it: I think you’d find this topic interesting – and my comments are actually too short for a paper or article, so I thought it would be good to throw it out here.

If you follow the weird world of quantum mechanics with some interest, you will have heard the latest news: the âpuzzleâ of the charge radius of the proton has been solved. To be precise, a more precise electron-proton scattering experiment by the PRad (proton radius) team using the Continuous Electron Beam Accelerator Facility (CEBAF) at Jefferson Lab has now measured the *root mean square *(rms) charge radius of the proton as[1]:

*r*_{p}Â =Â 0.831Â Â±Â 0.007_{stat}Â Â± 0.012_{syst}Â fm

If a proton would, somehow, have a pointlike elementary (electric) charge in it, and if it it is in some kind of circular motion (as we presume in *Zitterbewegung *models of elementary particles), then we can establish a simple relation between the magnetic moment (ÎŒ) and the radius (*a*) of the circular current.

Indeed, the magnetic moment is the current (I) times the surface area of the loop (Ï*a*^{2}), and the current is just the product of the elementary charge (q_{e}) and the frequency (*f*), which we can calculate as *f *= *c*/2Ï*a*, i.e. the velocity of the charge[2] divided by the circumference of the loop. We write:Using the Compton radius of an electron (*a*_{e} = Ä§/m_{e}*c*), this yields the correct magnetic moment for the electron[3]:What radius do we get when applying the *a *= ÎŒ/0.24âŠÂŽ10^{â10} relation to the (experimentally measured) magnetic moment of a proton? I invite the reader to verify the next calculation using CODATA values:When I first calculated this, I thought: thatâs not good enough. I only have the *order of magnitude *right. However, when multiplying this with â2, we get a value which fits into the 0.831 Â± 0.007 interval. To be precise, we get this:

Of course, you will wonder: how can we justify the â2 factor? I am not sure. It is a *charge *radius. Hence, the electrons will bounce off because of the electromagnetic fields. The magnetic field of the current ring will be some envelope to the current ring itself. We would, therefore, expect the measured charge radius to be larger than the radius of the current ring (*a*). There are also the intricacies related to the definition of a *root mean square* (rms) radius.

I feel this can*not *be a coincidence: the difference between our âtheoreticalâ value (0.83065 fm) and the last precision measurement (0.831 fm) is only 0.00035 fm, which is only 5% of the statistical standard deviation (0.007 fm). Proton radius solved?

Maybe. Maybe not. The concluding comments of *Physics Today *were this: âThe PRad radius result, about 0.83 fm, agrees with the smaller value from muonic and now electronic hydrogen spectroscopy measurements. With that, it seems the puzzle is resolved, and the discrepancy was likely due to measurement errors. *Unfortunately, the conclusion requires no new physics*.â (my italics)

I wonder what kind of new physics they are talking about.

Jean Louis Van Belle, 24 January 2020

PS: I did make a paper out of this (see my academia.edu or viXra.org publications), and I shared it with the PRad team at JLAB. Prof. Dr. Ashot Gasparian was kind enough to acknowledge my email and thought “the approach and numbers are interesting.” Let us see what comes out of it. I need to get back to my day job. đ

[1] See: https://www.nature.com/articles/s41586-019-1721-2. See also: https://www.jlab.org/prad/collaboration.html and https://www.jlab.org/experiment-research.

[2] *Zitterbewegung *models assume an electron consists of a pointlike charge whizzing around some center. The *rest *mass of the pointlike charge is zero, which is why its velocity is equal to the speed of light. However, because of its motion, it acquires an *effective *mass â pretty much like a photon, which has mass because of its motion. One can show the effective mass of the pointlike charge â which is a relativistic mass concept â is half the rest mass of the electron: m_{Îł} = m_{e}/2.

[3] The calculations do away with the niceties of the + or â sign conventions as they focus on the *values *only. We also invite the reader to add the SI units so as to make sure all equations are consistent from a *dimensional *point of view. For the values themselves, see the CODATA values on the NIST website (https://physics.nist.gov/cuu/Constants/index.html).